AramJonghu/rustlings
1
0
Fork 0
mirror of https://git.aramjonghu.dev/AramJonghu/rustlings.git synced 2026-09-04 01:03:31 +02:00
Code Issues Packages Projects Releases Wiki Activity

Add solutions to functions

Browse Source
This commit is contained in:
mo8it
2024-05-21 02:43:18 +02:00
parent 0f4c42d54e
commit d0b843d6c4
13 changed files with 97 additions and 41 deletions
Download Patch File Download Diff File Expand all files Collapse all files
rustlings-macros/info.toml
+11 -11
View File
@@ -142,7 +142,7 @@ test = false
hint = """
This `main` function is calling a function that it expects to exist, but the
function doesn't exist. It expects this function to have the name `call_me`.
It expects this function to not take any arguments and not return a value.
It also expects this function to not take any arguments and not return a value.
Sounds a lot like `main`, doesn't it?"""
[[exercises]]
@@ -159,7 +159,7 @@ dir = "02_functions"
test = false
hint = """
This time, the function *declaration* is okay, but there's something wrong
with the place where we're calling the function."""
with the place where we are calling the function."""
[[exercises]]
name = "functions4"
@@ -167,8 +167,8 @@ dir = "02_functions"
test = false
hint = """
The error message points to the function `sale_price` and says it expects a type
after the `->`. This is where the function's return type should be -- take a
look at the `is_even` function for an example!"""
after `->`. This is where the function's return type should be.
Take a look at the `is_even` function for an example!"""
[[exercises]]
name = "functions5"
@@ -177,15 +177,15 @@ test = false
hint = """
This is a really common error that can be fixed by removing one character.
It happens because Rust distinguishes between expressions and statements:
expressions return a value based on their operand(s), and statements simply
return a `()` type which behaves just like `void` in C/C++ language.
Expressions return a value based on their operand(s), and statements simply
return a `()` type which behaves just like `void` in C/C++.
We want to return a value of `i32` type from the `square` function, but it is
returning a `()` type...
We want to return a value with the type `i32` from the `square` function, but
it is returning the type `()`.
They are not the same. There are two solutions:
1. Add a `return` ahead of `num * num;`
2. remove `;`, make it to be `num * num`"""
There are two solutions:
1. Add the `return` keyword before `num * num;`
2. Remove the semicolon `;` after `num * num`"""
# IF